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simpler exercise for now
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@ -1,281 +0,0 @@
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Implement a doubly linked list similar to the following:
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```c
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#include <stdio.h>
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#include <string.h>
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#include <stdlib.h>
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#include <stdbool.h>
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struct node {
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int data;
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int key;
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struct node *next;
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struct node *prev;
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};
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//this link always point to first Link
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struct node *head = NULL;
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//this link always point to last Link
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struct node *last = NULL;
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struct node *current = NULL;
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//is list empty
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bool isEmpty() {
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return head == NULL;
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}
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int length() {
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int length = 0;
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struct node *current;
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for(current = head; current != NULL; current = current->next){
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length++;
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}
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return length;
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}
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//display the list in from first to last
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void displayForward() {
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//start from the beginning
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struct node *ptr = head;
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//navigate till the end of the list
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printf("\n[ ");
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while(ptr != NULL) {
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printf("(%d,%d) ",ptr->key,ptr->data);
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ptr = ptr->next;
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}
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printf(" ]");
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}
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//display the list from last to first
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void displayBackward() {
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//start from the last
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struct node *ptr = last;
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//navigate till the start of the list
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printf("\n[ ");
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while(ptr != NULL) {
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//print data
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printf("(%d,%d) ",ptr->key,ptr->data);
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//move to next item
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ptr = ptr ->prev;
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}
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}
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//insert link at the first location
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void insertFirst(int key, int data) {
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//create a link
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struct node *link = (struct node*) malloc(sizeof(struct node));
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link->key = key;
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link->data = data;
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if(isEmpty()) {
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//make it the last link
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last = link;
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} else {
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//update first prev link
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head->prev = link;
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}
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//point it to old first link
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link->next = head;
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//point first to new first link
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head = link;
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}
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//insert link at the last location
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void insertLast(int key, int data) {
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//create a link
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struct node *link = (struct node*) malloc(sizeof(struct node));
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link->key = key;
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link->data = data;
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if(isEmpty()) {
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//make it the last link
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last = link;
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} else {
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//make link a new last link
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last->next = link;
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//mark old last node as prev of new link
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link->prev = last;
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}
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//point last to new last node
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last = link;
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}
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//delete first item
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struct node* deleteFirst() {
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//save reference to first link
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struct node *tempLink = head;
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//if only one link
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if(head->next == NULL){
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last = NULL;
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} else {
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head->next->prev = NULL;
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}
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head = head->next;
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//return the deleted link
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return tempLink;
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}
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//delete link at the last location
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struct node* deleteLast() {
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//save reference to last link
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struct node *tempLink = last;
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//if only one link
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if(head->next == NULL) {
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head = NULL;
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} else {
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last->prev->next = NULL;
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}
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last = last->prev;
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//return the deleted link
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return tempLink;
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}
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//delete a link with given key
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struct node* delete(int key) {
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//start from the first link
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struct node* current = head;
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struct node* previous = NULL;
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//if list is empty
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if(head == NULL) {
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return NULL;
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}
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//navigate through list
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while(current->key != key) {
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//if it is last node
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if(current->next == NULL) {
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return NULL;
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} else {
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//store reference to current link
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previous = current;
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//move to next link
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current = current->next;
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}
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}
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//found a match, update the link
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if(current == head) {
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//change first to point to next link
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head = head->next;
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} else {
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//bypass the current link
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current->prev->next = current->next;
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}
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if(current == last) {
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//change last to point to prev link
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last = current->prev;
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} else {
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current->next->prev = current->prev;
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}
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return current;
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}
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bool insertAfter(int key, int newKey, int data) {
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//start from the first link
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struct node *current = head;
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//if list is empty
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if(head == NULL) {
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return false;
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}
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//navigate through list
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while(current->key != key) {
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//if it is last node
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if(current->next == NULL) {
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return false;
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} else {
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//move to next link
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current = current->next;
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}
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}
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//create a link
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struct node *newLink = (struct node*) malloc(sizeof(struct node));
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newLink->key = newKey;
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newLink->data = data;
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if(current == last) {
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newLink->next = NULL;
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last = newLink;
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} else {
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newLink->next = current->next;
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current->next->prev = newLink;
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}
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newLink->prev = current;
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current->next = newLink;
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return true;
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}
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void main() {
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insertFirst(1,10);
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insertFirst(2,20);
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insertFirst(3,30);
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insertFirst(4,1);
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insertFirst(5,40);
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insertFirst(6,56);
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printf("\nList (First to Last): ");
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displayForward();
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printf("\n");
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printf("\nList (Last to first): ");
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displayBackward();
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printf("\nList , after deleting first record: ");
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deleteFirst();
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displayForward();
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printf("\nList , after deleting last record: ");
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deleteLast();
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displayForward();
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printf("\nList , insert after key(4) : ");
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insertAfter(4,7, 13);
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displayForward();
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printf("\nList , after delete key(4) : ");
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delete(4);
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displayForward();
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}
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```
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Instead of maintaining head, last, and current in the global; maintain them inside main() and send them as reference to the functions, as required. Feel free to change function arguments as required.
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@ -1,83 +0,0 @@
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/* define your structure here
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*/
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fn isEmpty(???) -> bool {
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}
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fn length(???, ???) -> i32 {
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}
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fn displayForward(???) {
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}
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fn displayBackward(???) {
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}
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fn insertFirst(???, key: i32, data: i32) {
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}
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fn insertLast(???, key: i32, data: i32) {
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}
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fn deleteFirst(???, ???) -> ???{
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}
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fn deleteLast(???, ???) -> ??? {
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}
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fn delete(???, ???, ???, key: i32) -> ??? {
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}
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fn insertAfter(???, ???, ???, key: i32, newKey: i32, data: i32) -> bool{
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}
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void main() {
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/* declare your nodes here for head, last, and current
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*/
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insertFirst(???, 1, 10);
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insertFirst(???, 2, 20);
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insertFirst(???, 3, 30);
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insertFirst(???, 4, 1);
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insertFirst(???, 5, 40);
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insertFirst(???, 6, 56);
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println!("\nList (First to Last): ");
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displayForward(???);
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println!("\n");
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println!("\nList (Last to first): ");
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displayBackward(???);
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println!("\nList , after deleting first record: ");
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deleteFirst(???, ???);
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displayForward(???);
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println!("\nList , after deleting last record: ");
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deleteLast(???, ???);
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displayForward(???);
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println!("\nList , insert after key(4) : ");
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insertAfter(???, ???, ???, 4, 7, 13);
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displayForward(???);
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println!("\nList , after delete key(4) : ");
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delete(???, ???, ???, 4);
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displayForward(???);
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}
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6
exercises/students/README.md
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6
exercises/students/README.md
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In this assignment, you will practice writing code relating to struct and ownership. Follow the code comments.
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- Ensure you are not missing any shorthands possible we have discussed.
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- Define methods means you call that using a `instance.fn()` approach.
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- You can have regular functions to iterate over the vector and sorting (ascending or descending) reason.
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- Make sure you follow best practices.
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- Minimize number of warnings, if possible to zero.
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38
exercises/students/students.rs
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38
exercises/students/students.rs
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struct Student {
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name: String,
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id: i32,
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major: String,
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gradyear: i32,
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}
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// define associate functions to create the following instances, use shorthand wherever available
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// define methods to satisfy the requirements
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// define functions to satisfy the requirements
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fn main() {
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// a vector<Student> and push the following instances
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// an instance of student (Adam Helex, 1022, CS, 2022)
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// an instance of student (Rob Delon, 1033, Bio, 2023)
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// an instance of student (Jenny Susan, 1044, CS, 2023)
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// an instance of student (Nick Frank, 1055, CS, 2022)
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// an instance of student (Michael Dodge, 1066, Bio, 2023)
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// Note: shorthand possible for Rob and Michael; Adam and Helex
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// call a function that will return list of students graduating by year
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// call a function that will return list of the last name of students
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// call a function that will sort the students by their first name
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// call a method that will return true if any two students are graduating same year
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// call a method that will modify the student last name to a desired one
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}
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Loading…
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Reference in New Issue
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